Relationship between current and voltage and resistance(Expansion – lead me deeper)

Relating voltage, current and resistance

Setting up a simple circuit consists of selecting two components–the battery and the bulb, and linking them with wires. The two choices you make set the push: the voltage of the battery, and how much that push is impeded: the resistance of the bulb. The current in the loop is the result of these two choices. Much more on this in the SPT: Electricity and energy topic.

The relationship between the push of the battery and the size of electric current is summarised by:

current = voltageresistance

You can write this out in symbols:

I = VR

Where V is voltage, measured in volt; I is current, measured in ampere; R is resistance, measured in ohm.

According to this relationship, if the resistance does not change, then increasing the voltage results in an increase in current.

Choosing a 3 volt battery and a 10 ohm resistor results in a current of 0.3 ampere in the resistor (and in the battery, and in the connecting wires).

I = VR

Put in the values to get:

current in loop = 3 volt10 ohm

and work out the current as 0.3 ampere.

If the battery voltage is doubled to 6 volt, the new current is still given by I = VR, but you need to insert the new values current in loop now = 6 volt10 ohm and calulate the current as 0.6 ampere.

There is a 0.6 ampere current in each part of the circuit loop: in the lamp; in the battery; in both the connecting wires.

Double the battery voltage gives double the current.

Prepare for teaching across the topic using these links

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This is a nugget in the PN thread – connect all three threads from any link

Physics Narrative (PN) Teaching & Learning Issues(TL) Teaching Approaches(TA)

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